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5774
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Programación / ASM / Re: Color de fondo,no coinicde!
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en: 24 Abril 2010, 20:58 pm
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Y con SendMessage?
EM_SETBKGNDCOLOR
The EM_SETBKGNDCOLOR message sets the background color for a rich edit control.
EM_SETBKGNDCOLOR
wParam = (WPARAM) (BOOL) fUseSysColor;
lParam = (LPARAM) (COLORREF) clr;
Parameters
fUseSysColor
Value specifying whether to use the system color. If this parameter is nonzero, the background is set to the window background system color. Otherwise, the background is set to the specified color.
clr
COLORREF structure specifying the color if fUseSysColor is zero.
Return Values
Returns the old background color.
Seria algo así: invoke GetDC,handle_del_static
invoke SendMessage,eax,EM_SETBKGNDCOLOR,1,0
wParam es 1, por lo que se usa el color por defecto del sistema. Si usas un 0 en wParam, en lParam le deberás pasar el color que quieres, de acuerdo a:
COLORREF
The COLORREF value is a 32-bit value used to specify an RGB color.
Remarks
When specifying an explicit RGB color, the COLORREF value has the following hexadecimal form:
0x00bbggrr
The low-order byte contains a value for the relative intensity of red; the second byte contains a value for green; and the third byte contains a value for blue. The high-order byte must be zero. The maximum value for a single byte is 0xFF.
Saludos! |
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5777
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Programación / Ingeniería Inversa / Re: ayuda con softice
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en: 19 Abril 2010, 00:27 am
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Hola!
Te recomiendo cambiar de debugger. Sice ya está viejito (no quiero decir que sea obsoleto, pero hoy en día tienes mejores opciones).
Para Ingeniería Inversa, lo mejor es OllyDbg debido a la info que hay dando vueltas de él. Si quieres depurar en ring 0, puedes usar WinDbg...
Saludos!
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5778
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Programación / Programación Visual Basic / Re: modulo clss md5
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en: 18 Abril 2010, 17:15 pm
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Quizás esto te ayude: VERSION 1.0 CLASS
BEGIN
MultiUse = -1 'True
Persistable = 0 'NotPersistable
DataBindingBehavior = 0 'vbNone
DataSourceBehavior = 0 'vbNone
MTSTransactionMode = 0 'NotAnMTSObject
END
Attribute VB_Name = "MD5"
Attribute VB_GlobalNameSpace = False
Attribute VB_Creatable = True
Attribute VB_PredeclaredId = False
Attribute VB_Exposed = False
Option Explicit
' CLASE: MD5
'
' DESCRIPCION:
' Esta es una clase que encapsula un grupo de funciones del Algoritmo MD5.
' El MD5 produce firmas digitales de 128 bits para bases de datos de cualquier largo.
' Detalles en el RFC 1321. Esta implementación está derivada de la implementacion del
' algoritmo MD5 de la RSA Data Security, Inc. (originalmente en C)
'
' AUTOR:
' Robert M. Hubley 12/1999
' Modificado y traducido por MCKSys Argentina 2009
'
'
'=
'= Constantes de clase
'=
Private Const OFFSET_4 = 4294967296#
Private Const MAXINT_4 = 2147483647
Private Const S11 = 7
Private Const S12 = 12
Private Const S13 = 17
Private Const S14 = 22
Private Const S21 = 5
Private Const S22 = 9
Private Const S23 = 14
Private Const S24 = 20
Private Const S31 = 4
Private Const S32 = 11
Private Const S33 = 16
Private Const S34 = 23
Private Const S41 = 6
Private Const S42 = 10
Private Const S43 = 15
Private Const S44 = 21
'=
'= Variables de clase
'=
Private Estado(4) As Long
Private CuentaBytes As Long
Private BufferDeBytes(63) As Byte
'=
'= Propiedades de la clase
'=
Property Get RegisterA() As String
RegisterA = Estado(1)
End Property
Property Get RegisterB() As String
RegisterB = Estado(2)
End Property
Property Get RegisterC() As String
RegisterC = Estado(3)
End Property
Property Get RegisterD() As String
RegisterD = Estado(4)
End Property
'=
'= Funciones de clase
'=
'
' haya MD5 de matriz de bytes en una cadena Hexadecimal
'
Public Function DigestArrayToHexStr(Matriz() As Byte) As String
MD5Init
MD5Update UBound(Matriz) + 1, Matriz
MD5Final
DigestArrayToHexStr = GetValues
End Function
'
' Concatenar los 4 valores de Estado en un solso string
'
Public Function GetValues() As String
GetValues = LongToString(Estado(1)) & LongToString(Estado(2)) & LongToString(Estado(3)) & LongToString(Estado(4))
End Function
'
' Convertir Long a cadena Hex
'
Private Function LongToString(Num As Long) As String
Dim a As Byte
Dim b As Byte
Dim c As Byte
Dim d As Byte
a = Num And &HFF&
If a < 16 Then
LongToString = "0" & Hex(a)
Else
LongToString = Hex(a)
End If
b = (Num And &HFF00&) \ 256
If b < 16 Then
LongToString = LongToString & "0" & Hex(b)
Else
LongToString = LongToString & Hex(b)
End If
c = (Num And &HFF0000) \ 65536
If c < 16 Then
LongToString = LongToString & "0" & Hex(c)
Else
LongToString = LongToString & Hex(c)
End If
If Num < 0 Then
d = ((Num And &H7F000000) \ 16777216) Or &H80&
Else
d = (Num And &HFF000000) \ 16777216
End If
If d < 16 Then
LongToString = LongToString & "0" & Hex(d)
Else
LongToString = LongToString & Hex(d)
End If
End Function
'
' Inicializar la clase
' Esto debe llamarse antes de realizar cualquier cálculo
'
Public Sub MD5Init()
CuentaBytes = 0
Estado(1) = UnsignedToLong(1732584193#)
Estado(2) = UnsignedToLong(4023233417#)
Estado(3) = UnsignedToLong(2562383102#)
Estado(4) = UnsignedToLong(271733878#)
End Sub
'
' MD5 Final
'
Public Sub MD5Final()
Dim dblBits As Double
Dim padding(72) As Byte
Dim lngBytesBuffered As Long
padding(0) = &H80
dblBits = CuentaBytes * 8
' rellenar
lngBytesBuffered = CuentaBytes Mod 64
If lngBytesBuffered <= 56 Then
MD5Update 56 - lngBytesBuffered, padding
Else
MD5Update 120 - CuentaBytes, padding
End If
padding(0) = UnsignedToLong(dblBits) And &HFF&
padding(1) = UnsignedToLong(dblBits) \ 256 And &HFF&
padding(2) = UnsignedToLong(dblBits) \ 65536 And &HFF&
padding(3) = UnsignedToLong(dblBits) \ 16777216 And &HFF&
padding(4) = 0
padding(5) = 0
padding(6) = 0
padding(7) = 0
MD5Update 8, padding
End Sub
'
' Partir datos de entrada en pedazos de 64 bytes
'
Public Sub MD5Update(InputLen As Long, InputBuffer() As Byte)
Dim II As Integer
Dim i As Integer
Dim j As Integer
Dim K As Integer
Dim lngBufferedBytes As Long
Dim lngBufferRemaining As Long
Dim lngRem As Long
lngBufferedBytes = CuentaBytes Mod 64
lngBufferRemaining = 64 - lngBufferedBytes
CuentaBytes = CuentaBytes + InputLen
' usar primero los resultados viejos del buffer
If InputLen >= lngBufferRemaining Then
For II = 0 To lngBufferRemaining - 1
BufferDeBytes(lngBufferedBytes + II) = InputBuffer(II)
Next II
MD5Transform BufferDeBytes
lngRem = (InputLen) Mod 64
' El transformador es multiplo de 64 asi que hagamos algunas transformaciones
For i = lngBufferRemaining To InputLen - II - lngRem Step 64
For j = 0 To 63
BufferDeBytes(j) = InputBuffer(i + j)
Next j
MD5Transform BufferDeBytes
Next i
lngBufferedBytes = 0
Else
i = 0
End If
' Buffear datos restantes
For K = 0 To InputLen - i - 1
BufferDeBytes(lngBufferedBytes + K) = InputBuffer(i + K)
Next K
End Sub
'
' MD5 Transform
'
Private Sub MD5Transform(Buffer() As Byte)
Dim x(16) As Long
Dim a As Long
Dim b As Long
Dim c As Long
Dim d As Long
a = Estado(1)
b = Estado(2)
c = Estado(3)
d = Estado(4)
Decode 64, x, Buffer
' Pasada 1
FF a, b, c, d, x(0), S11, -680876936
FF d, a, b, c, x(1), S12, -389564586
FF c, d, a, b, x(2), S13, 606105819
FF b, c, d, a, x(3), S14, -1044525330
FF a, b, c, d, x(4), S11, -176418897
FF d, a, b, c, x(5), S12, 1200080426
FF c, d, a, b, x(6), S13, -1473231341
FF b, c, d, a, x(7), S14, -45705983
FF a, b, c, d, x(8), S11, 1770035416
FF d, a, b, c, x(9), S12, -1958414417
FF c, d, a, b, x(10), S13, -42063
FF b, c, d, a, x(11), S14, -1990404162
FF a, b, c, d, x(12), S11, 1804603682
FF d, a, b, c, x(13), S12, -40341101
FF c, d, a, b, x(14), S13, -1502002290
FF b, c, d, a, x(15), S14, 1236535329
' Pasada 2
GG a, b, c, d, x(1), S21, -165796510
GG d, a, b, c, x(6), S22, -1069501632
GG c, d, a, b, x(11), S23, 643717713
GG b, c, d, a, x(0), S24, -373897302
GG a, b, c, d, x(5), S21, -701558691
GG d, a, b, c, x(10), S22, 38016083
GG c, d, a, b, x(15), S23, -660478335
GG b, c, d, a, x(4), S24, -405537848
GG a, b, c, d, x(9), S21, 568446438
GG d, a, b, c, x(14), S22, -1019803690
GG c, d, a, b, x(3), S23, -187363961
GG b, c, d, a, x(8), S24, 1163531501
GG a, b, c, d, x(13), S21, -1444681467
GG d, a, b, c, x(2), S22, -51403784
GG c, d, a, b, x(7), S23, 1735328473
GG b, c, d, a, x(12), S24, -1926607734
' Pasada 3
HH a, b, c, d, x(5), S31, -378558
HH d, a, b, c, x(8), S32, -2022574463
HH c, d, a, b, x(11), S33, 1839030562
HH b, c, d, a, x(14), S34, -35309556
HH a, b, c, d, x(1), S31, -1530992060
HH d, a, b, c, x(4), S32, 1272893353
HH c, d, a, b, x(7), S33, -155497632
HH b, c, d, a, x(10), S34, -1094730640
HH a, b, c, d, x(13), S31, 681279174
HH d, a, b, c, x(0), S32, -358537222
HH c, d, a, b, x(3), S33, -722521979
HH b, c, d, a, x(6), S34, 76029189
HH a, b, c, d, x(9), S31, -640364487
HH d, a, b, c, x(12), S32, -421815835
HH c, d, a, b, x(15), S33, 530742520
HH b, c, d, a, x(2), S34, -995338651
' Pasada 4
II a, b, c, d, x(0), S41, -198630844
II d, a, b, c, x(7), S42, 1126891415
II c, d, a, b, x(14), S43, -1416354905
II b, c, d, a, x(5), S44, -57434055
II a, b, c, d, x(12), S41, 1700485571
II d, a, b, c, x(3), S42, -1894986606
II c, d, a, b, x(10), S43, -1051523
II b, c, d, a, x(1), S44, -2054922799
II a, b, c, d, x(8), S41, 1873313359
II d, a, b, c, x(15), S42, -30611744
II c, d, a, b, x(6), S43, -1560198380
II b, c, d, a, x(13), S44, 1309151649
II a, b, c, d, x(4), S41, -145523070
II d, a, b, c, x(11), S42, -1120210379
II c, d, a, b, x(2), S43, 718787259
II b, c, d, a, x(9), S44, -343485551
Estado(1) = LongOverflowAdd(Estado(1), a)
Estado(2) = LongOverflowAdd(Estado(2), b)
Estado(3) = LongOverflowAdd(Estado(3), c)
Estado(4) = LongOverflowAdd(Estado(4), d)
End Sub
Private Sub Decode(Length As Integer, OutputBuffer() As Long, InputBuffer() As Byte)
Dim intDblIndex As Integer
Dim intByteIndex As Integer
Dim dblSum As Double
intDblIndex = 0
For intByteIndex = 0 To Length - 1 Step 4
dblSum = InputBuffer(intByteIndex) + _
InputBuffer(intByteIndex + 1) * 256# + _
InputBuffer(intByteIndex + 2) * 65536# + _
InputBuffer(intByteIndex + 3) * 16777216#
OutputBuffer(intDblIndex) = UnsignedToLong(dblSum)
intDblIndex = intDblIndex + 1
Next intByteIndex
End Sub
'
' FF, GG, HH, y II para las transformaciones de la Pasada 1, 2, 3 y 4.
' La rotación es separada de la suma para prevenir recálculos
'
Private Function FF(a As Long, _
b As Long, _
c As Long, _
d As Long, _
x As Long, _
s As Long, _
ac As Long) As Long
a = LongOverflowAdd4(a, (b And c) Or (Not (b) And d), x, ac)
a = LongLeftRotate(a, s)
a = LongOverflowAdd(a, b)
End Function
Private Function GG(a As Long, _
b As Long, _
c As Long, _
d As Long, _
x As Long, _
s As Long, _
ac As Long) As Long
a = LongOverflowAdd4(a, (b And d) Or (c And Not (d)), x, ac)
a = LongLeftRotate(a, s)
a = LongOverflowAdd(a, b)
End Function
Private Function HH(a As Long, _
b As Long, _
c As Long, _
d As Long, _
x As Long, _
s As Long, _
ac As Long) As Long
a = LongOverflowAdd4(a, b Xor c Xor d, x, ac)
a = LongLeftRotate(a, s)
a = LongOverflowAdd(a, b)
End Function
Private Function II(a As Long, _
b As Long, _
c As Long, _
d As Long, _
x As Long, _
s As Long, _
ac As Long) As Long
a = LongOverflowAdd4(a, c Xor (b Or Not (d)), x, ac)
a = LongLeftRotate(a, s)
a = LongOverflowAdd(a, b)
End Function
'
' Rotar un long a la derecha
'
Function LongLeftRotate(value As Long, bits As Long) As Long
Dim lngSign As Long
Dim lngI As Long
bits = bits Mod 32
If bits = 0 Then LongLeftRotate = value: Exit Function
For lngI = 1 To bits
lngSign = value And &HC0000000
value = (value And &H3FFFFFFF) * 2
value = value Or ((lngSign < 0) And 1) Or (CBool(lngSign And _
&H40000000) And &H80000000)
Next
LongLeftRotate = value
End Function
'
' Función para sumar 2 numeros sin signo como en C.
' los desbordamientos se ignoran!
'
Private Function LongOverflowAdd(Val1 As Long, Val2 As Long) As Long
Dim lngHighWord As Long
Dim lngLowWord As Long
Dim lngOverflow As Long
lngLowWord = (Val1 And &HFFFF&) + (Val2 And &HFFFF&)
lngOverflow = lngLowWord \ 65536
lngHighWord = (((Val1 And &HFFFF0000) \ 65536) + ((Val2 And &HFFFF0000) \ 65536) + lngOverflow) And &HFFFF&
LongOverflowAdd = UnsignedToLong((lngHighWord * 65536#) + (lngLowWord And &HFFFF&))
End Function
'
' Función para sumar 2 numeros sin signo como en C.
' los desbordamientos se ignoran!
'
Private Function LongOverflowAdd4(Val1 As Long, Val2 As Long, val3 As Long, val4 As Long) As Long
Dim lngHighWord As Long
Dim lngLowWord As Long
Dim lngOverflow As Long
lngLowWord = (Val1 And &HFFFF&) + (Val2 And &HFFFF&) + (val3 And &HFFFF&) + (val4 And &HFFFF&)
lngOverflow = lngLowWord \ 65536
lngHighWord = (((Val1 And &HFFFF0000) \ 65536) + _
((Val2 And &HFFFF0000) \ 65536) + _
((val3 And &HFFFF0000) \ 65536) + _
((val4 And &HFFFF0000) \ 65536) + _
lngOverflow) And &HFFFF&
LongOverflowAdd4 = UnsignedToLong((lngHighWord * 65536#) + (lngLowWord And &HFFFF&))
End Function
'
' Convertir un double sin signo en un long
'
Private Function UnsignedToLong(value As Double) As Long
If value < 0 Or value >= OFFSET_4 Then Error 6 ' Desbordamiento
If value <= MAXINT_4 Then
UnsignedToLong = value
Else
UnsignedToLong = value - OFFSET_4
End If
End Function
'
' Convertir un long en un Double sin signo
'
Private Function LongToUnsigned(value As Long) As Double
If value < 0 Then
LongToUnsigned = value + OFFSET_4
Else
LongToUnsigned = value
End If
End Function
Saludos! |
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5780
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Programación / Programación Visual Basic / Re: [Source] VB6 Bruteforce (mejorado)
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en: 16 Abril 2010, 03:38 am
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Esta es una alternativa con 2 bucles: Sub BruteForce(MaxDigitos As Integer)
'a = 97
'z = 122
Dim Serial As String
Dim Terminado As Boolean
Dim Terminado2 As Boolean
Dim i As Integer
Dim c As Byte
Dim j As Integer
Dim pos As Integer
Serial = Space(MaxDigitos)
Open App.Path & "\midicionario.txt" For Output As #1
Mid(Serial, 1, 1) = "a"
Print #1, Trim(Serial)
Terminado = False
Do While Not Terminado
pos = 1
Terminado2 = False
Do While Not Terminado2
DoEvents
c = Asc(Mid(Serial, pos, 1))
'contempla char espacio
If c < 97 Then
c = 97
Else
c = c + 1
End If
If c < 123 Then
Mid(Serial, pos, 1) = Chr(c)
Terminado2 = True
Else
Mid(Serial, pos, 1) = "a"
pos = pos + 1
End If
Loop
Print #1, Trim(Serial)
Terminado = True
For j = 1 To MaxDigitos
Terminado = Terminado And (Mid(Serial, j, 1) = "z")
Next j
Loop
Close #1
MsgBox "listo"
End Sub
Saludos! |
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