for (i = 0; i < esp; i++)
   putchar(' ');
for (i = 0; i < sign; i++)
   putchar('#');
putchar('\n');

for(cociente = numero;cociente > 0;cociente/=16){
   residuo = cociente % 16;
   num_hex = convertirHexadecimal(residuo);
   sprintf(c,"%c",num_hex);
   strcat(cadena,c);
}

#include <stdio.h>
#include <stdlib.h>
 
int main(void)
{
   printf("%d %x %04x\n", 33, 33, 33); /* Imprime 33 21 0021 */
 
   return EXIT_SUCCESS;
}

#include <stdio.h>
#include <stdlib.h>
 
int main(void)
{
   const int a = 42;
 
   a = 69;
   printf("%d\n", a);
 
   return EXIT_SUCCESS;
}

Lc.exe -A -ansic -check main.c

main.c:8:Error:assignment to const identifier 'a'
----
Pocc /Zs /W2 main.c

main.c(8): error #2032: Assignment to const identifier 'a'.
----
gcc (GCC) 4.7.3
gcc.exe -c -ansi -pedantic -Wall -O main.c -o main.tmp

main.c: In function ‘main’:
main.c:8:4: error: assignment of read-only variable ‘a’
----
CL.exe /TC /Zs /Za /Wall /W4 /D_CRT_SECURE_NO_WARNINGS main.c

main.c(8) : error C2166: Valor L especifica un objeto const

#include <stdio.h>
#include <stdlib.h>
 
int main(void)
{
   char *s = "anita lava la tina";
   char *t = "tina";
 
   int i;
   int j;
 
   for (i = 0; s[i] != '\0'; i++){
      for (j = 0; s[i + j] == t[j] && t[j] != '\0'; j++)
         ;
 
      if (t[j] == '\0')
         printf("Coincidencia en la posicion %d\n", i);
   }
 
   return EXIT_SUCCESS;
}

while ((c = getchar()) != EOF && c != '\n')
   ;

printf("Definir tama%co aproximado de la cadena: ", 164);

void baraja( int wMazo[4][13] );
 
/* O tambien */
void baraja( int wMazo[][13] );

void baraja(int (*wMazo)[13]);

if (a[n] == p == a[i]) {

if (a[n] == p) {

a[n] == p == a[i];

#include <stdio.h>
 
int main(void)
{
   int i, j, inicio, final;
   char cadena[100] = "3 * 5 + (9 - 2) + 5", auxiliar[100];
 
   for (i = 0; cadena[i]; i++){
      if (cadena[i] == '(')
         inicio = i;
      if (cadena[i] == ')') {
         final = i;
         break;
      }
   }
 
   for (i = inicio + 1, j = 0; i < final; i++, j++)
      auxiliar[j] = cadena[i];
   auxiliar[j] = '\0';
 
   for (i = inicio; i <= final; i++)
      cadena[i] = ' ';
 
   printf("auxiliar = \"%s\", cadena = \"%s\"\n", auxiliar, cadena);
 
   return 0;
}

#include <stdio.h>
#include <string.h>
 
int main(void)
{
   char *s = "3 * 5 + (9 - 2) + 5";
   char *p;
   char *q;
 
   if ((p = strchr(s, '(')) && (q = strchr(p, ')')))
      printf("%.*s\n", (int) (q - p + 1), p);
 
   return 0;
}

#include <stdio.h>
#include <stdlib.h>
 
int main(void)
{
   int (*p)(const char *) = puts;
 
   p("puntero");
   puts("identificador ==> puntero");
   (*p)("expresion ==> puntero");
 
   return EXIT_SUCCESS;
}