<!DOCTYPE html>
<script src="jquery-3.1.0.js" type="text/javascript"></script>
<form class="formulario"> <p><input type="text "id="clickme" value="n o m b r e"></p> <p><input type="text "id="pass" value=" c o n t r a s e n a"></p> <input type="submit" id="botonEnviar" value="enviar">
var id="idUsuario";
$('.formulario').submit(function(event) {
form_submit();
return false;
});
function form_submit() {
var request = $.ajax({
url: 'login.php',
type: 'POST',
data: {
keystrokes : id
},
dataType: 'json',
contentType:'application/json',
});
request.done(function(response) {
alert((response.status ? "Success: " : "Error: ") + response.message);
if(response.status) {
window.location.href = 'login.php';
}
else {
window.location.href = '';
}
});
request.fail(function(jqXHR, textStatus) {
alert("Server request failed: " + textStatus);
window.location.href = '';
});
request.error(function(result, sts,err) {
alert(err+":"+sts);
});
}
<?php
$resultado = $_POST['keystrokes'];
echo $resultado;
?>
el error que me sale es parseerror, como lo soluciono ?