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You have devised a new encryption technique which encodes a message by inserting between its characters
randomly generated strings in a clever way. Because of pending patent issues we will not discuss in
detail how the strings are generated and inserted into the original message. To validate your method,
however, it is necessary to write a program that checks if the message is really encoded in the final
string.
Given two strings s and t, you have to decide whether s is a subsequence of t, i.e. if you can remove
characters from t such that the concatenation of the remaining characters is s.
Input
The input contains several testcases. Each is specified by two strings s, t of alphanumeric ASCII
characters separated by whitespace. Input is terminated by EOF.
Output
For each test case output, if s is a subsequence of t.
Sample Input
sequence subsequence
person compression
VERDI vivaVittorioEmanueleReDiItalia
caseDoesMatter CaseDoesMatter
Sample Output
Yes
No
Yes
No
randomly generated strings in a clever way. Because of pending patent issues we will not discuss in
detail how the strings are generated and inserted into the original message. To validate your method,
however, it is necessary to write a program that checks if the message is really encoded in the final
string.
Given two strings s and t, you have to decide whether s is a subsequence of t, i.e. if you can remove
characters from t such that the concatenation of the remaining characters is s.
Input
The input contains several testcases. Each is specified by two strings s, t of alphanumeric ASCII
characters separated by whitespace. Input is terminated by EOF.
Output
For each test case output, if s is a subsequence of t.
Sample Input
sequence subsequence
person compression
VERDI vivaVittorioEmanueleReDiItalia
caseDoesMatter CaseDoesMatter
Sample Output
Yes
No
Yes
No
y este es mi codigo, no se como solucionarlo, no funciona para todos los casos
Código
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.StringTokenizer; /** * a->97 z->122 A->65 A->90 * * @author qwery.azc */ public class Main { int piv = 0; int cajaIndex=0; for (int i = 0; i < cadenita.length(); i++) { char caracter=cadenita.charAt(i); for (int j = 0; j < cadenota.length() ; j++) { if (caracter == cadenota.charAt(j)) { piv++; i++; } } } if(piv==cadenita.length()){ res="Yes"; } return res; } Main m = new Main(); StringTokenizer stk; String line; String cad1,cad2; while ((line=scanner.readLine())!=null) { cad1=stk.nextToken(); cad2=stk.nextToken(); m.pertenecer(cad1, cad2); } scanner.close(); } }
aqui va la solucion, pero lo adapto y no da nada
http://solvingproblemsbd.blogspot.com/2014/09/uva-solution-10340-all-in-all.html