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Páginas: 1 [2]
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12
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Programación / .NET (C#, VB.NET, ASP) / VB: Cómo alinear la posición de dos rectángulos en proyecto Servidor - Cliente?
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en: 1 Enero 2016, 14:15 pm
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Tengo un problema en relación con dos rectángulos (en servidor y cliente, respectivamente). El rectángulo rojo se dibuja en el lado del servidor, y el rectángulo con un agujero se crea en el lado del cliente. Pero el rectángulo con el agujero que se dibuja en el lado del cliente, nunca se queda en la misma posición que ya se definió en Server. Todas las sugerencias son bienvenidas. Por lo tanto, mi resultado hasta ahora esto es: Del lado del servidorDim mRect As Rectangle Dim d
'=========================== DRAW RECTANGLE IN PICTUREBOX ===================================
Private Sub PictureBoxREMOTO_MouseDown(sender As Object, e As MouseEventArgs) Handles PictureBoxREMOTO.MouseDown mRect = New Rectangle(e.X - d.x, e.Y - d.y, 0, 0) PictureBoxREMOTO.Invalidate() End Sub
Private Sub PictureBoxREMOTO_MouseMove(sender As Object, e As MouseEventArgs) Handles PictureBoxREMOTO.MouseMove
If e.Button = Windows.Forms.MouseButtons.Left Then
Dim gp As New System.Drawing.Drawing2D.GraphicsPath
mRect = New Rectangle(mRect.Left, mRect.Top, e.X - d.x - mRect.Left, e.Y - d.y - mRect.Top)
PictureBoxREMOTO.Invalidate() End If End Sub
Private Sub PictureBoxREMOTO_Paint(sender As Object, e As PaintEventArgs) Handles PictureBoxREMOTO.Paint Dim mRect2 = New Rectangle(mRect.Location, mRect.Size) mRect2.Offset(d)
Using pen As New Pen(Color.Red, 3) e.Graphics.DrawRectangle(pen, mRect2) End Using End Sub
Private Sub PictureBoxREMOTO_MouseUp(sender As Object, e As MouseEventArgs) Handles PictureBoxREMOTO.MouseUp
Dim MENSAJE As String = "HOLE:" & mRect.Left & ":" & mRect.Top & ":" & e.X - d.x - mRect.Left & ":" & e.Y - d.y - mRect.Top ENVIO = System.Text.Encoding.UTF7.GetBytes(MENSAJE)
'mRect = New Rectangle(e.X - d.x, e.Y - d.y, 0, 0) 'PictureBoxREMOTO.Invalidate()
End Sub
Private Sub Form1_Load(sender As Object, e As EventArgs) Handles MyBase.Load d = PictureBoxREMOTO.PointToClient(PictureBoxREMOTO.Location) End Sub
'=========================================================================================
Lado del clientePrivate j As Integer Private z As Integer Private l As Integer Private m As Integer
Private Sub DDMain() BeginInvoke(New Action(AddressOf Rise_DD)) End Sub
Private Sub Rise_DD()
Form2.m = j Form2.n = z Form2.o = l Form2.p = m
Form2.Button1_Click(Me, Nothing)
End Sub
Public Sub ORDENES(ByVal ORDEN As String)
Dim PARTES As String() = ORDEN.Split(":") POSICIONX = PARTES(1) POSICIONY = PARTES(2) Cursor.Position = New Point(POSICIONX, POSICIONY)
Select Case PARTES(0)
Case "HOLE"
'Coordinates of rectangle drawn on Server
j = PARTES(1) z = PARTES(2) l = PARTES(3) m = PARTES(4)
DDMain()
'MessageBox.Show(PARTES(1) & " - " & PARTES(2) & " - " & PARTES(3) & " - " & PARTES(4)) 'Coordinates of rectangle drawed on Server
End Select
End Sub
Form2 del lado del clientePublic m As Integer Public n As Integer Public o As Integer Public p As Integer
Public Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim mRect As Rectangle
Dim gp As New System.Drawing.Drawing2D.GraphicsPath
gp.AddRectangle(New Rectangle(0, 0, Me.Width, Me.Height))
mRect = New Rectangle(m, n, o, p)
gp.AddRectangle(mRect)
Me.Region = New Region(gp)
Me.Invalidate()
End Sub
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13
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Programación / Programación Visual Basic / Re: VB6: Problema con función "ProcessExists"
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en: 24 Noviembre 2015, 18:32 pm
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LeandroA, las funciones anteriores no reconocen el nombre de mi programa para comprobar, por lo que cuando se está ejecutando, dicen que no es cierto (falso). Usted puede tratar de ver el nombre de su programa hecho en VB.NET (mi caso) no está funcionando. Ahora con otro programa funciona bien (por ejemplo, "chrome.exe"). Es decir, las funciones anteriores fallan para verificar algunos nombres de proceso.
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15
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Programación / Programación Visual Basic / VB6: Problema con función "ProcessExists"
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en: 24 Noviembre 2015, 14:58 pm
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Buen día amigos, Tengo dos funciones que sirven para verificar si un proceso que ya está en marcha, pero return false cuando el proceso se está ejecutando. ¿Podría alguien ayudarme con esto, por favor? Aquí dejo las funciones que estoy utilizando:
''''''''''''''''''''''''''''''''' PROCESS EXISTS '''''''''''''''''''''
Private Const MAX_PATH = 260 Private Const PROCESS_QUERY_INFORMATION = &H400
Private Declare Function OpenProcess Lib "kernel32" ( _ ByVal dwDesiredAccess As Long, ByVal bInheritHandle As Long, ByVal dwProcessID As Long) As Long Private Declare Function EnumProcesses Lib "PSAPI.DLL" ( _ lpidProcess As Long, ByVal cb As Long, cbNeeded As Long) As Long Private Declare Function EnumProcessModules Lib "PSAPI.DLL" ( _ ByVal hProcess As Long, lphModule As Long, ByVal cb As Long, lpcbNeeded As Long) As Long Private Declare Function GetModuleBaseName Lib "PSAPI.DLL" Alias "GetModuleBaseNameA" ( _ ByVal hProcess As Long, ByVal hModule As Long, ByVal lpFileName As String, ByVal nSize As Long) As Long Private Const PROCESS_VM_READ = &H10 Private Const PROCESS_QUERY_INFORMATION = &H400
Private Type PROCESSENTRY32 dwSize As Long cntUsage As Long th32ProcessID As Long th32DefaultHeapID As Long th32ModuleID As Long cntThreads As Long th32ParentProcessID As Long pcPriClassBase As Long dwFlags As Long szExeFile As String * MAX_PATH End Type Private Declare Function CreateToolhelpSnapshot Lib "kernel32" Alias "CreateToolhelp32Snapshot" (ByVal lFlags As Long, ByVal lProcessID As Long) As Long Private Const TH32CS_SNAPPROCESS As Long = 2& Private Declare Function GetWindowThreadProcessId Lib "user32" (ByVal hWnd As Long, lpdwProcessId As Long) As Long Private Declare Function ProcessFirst Lib "kernel32" Alias "Process32First" (ByVal hSnapshot As Long, uProcess As PROCESSENTRY32) As Long Private Declare Function ProcessNext Lib "kernel32" Alias "Process32Next" (ByVal hSnapshot As Long, uProcess As PROCESSENTRY32) As Long Private Declare Function CloseHandle Lib "kernel32" (ByVal hObject As Long) As Long
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Private Function FindProcessID(ByVal pExename As String) As Long
Dim ProcessID As Long, hSnapshot As Long Dim uProcess As PROCESSENTRY32, rProcessFound As Long Dim Pos As Integer, szExename As String hSnapshot = CreateToolhelpSnapshot(TH32CS_SNAPPROCESS, 0&) If hSnapshot = -1 Then Exit Function End If uProcess.dwSize = Len(uProcess) rProcessFound = ProcessFirst(hSnapshot, uProcess) Do While rProcessFound Pos = InStr(1, uProcess.szExeFile, vbNullChar) If Pos Then szExename = Left$(uProcess.szExeFile, Pos - 1) End If If LCase$(szExename) = LCase$(pExename) Then ProcessID = uProcess.th32ProcessID Exit Do Else rProcessFound = ProcessNext(hSnapshot, uProcess) End If Loop CloseHandle hSnapshot FindProcessID = ProcessID
End Function
Private Function IsProcessRunning2(PID As Long) As Boolean Dim hProcess As Long hProcess = OpenProcess(PROCESS_QUERY_INFORMATION, 0, PID) CloseHandle hProcess IsProcessRunning2 = hProcess End Function
Private Function IsProcessRunning(ByVal sProcess As String) As Boolean Const MAX_PATH As Long = 260 Dim lProcesses() As Long, lModules() As Long, N As Long, lRet As Long, hProcess As Long Dim sName As String sProcess = UCase$(sProcess) ReDim lProcesses(1023) As Long If EnumProcesses(lProcesses(0), 1024 * 4, lRet) Then For N = 0 To (lRet \ 4) - 1 hProcess = OpenProcess(PROCESS_QUERY_INFORMATION Or PROCESS_VM_READ, 0, lProcesses(N)) If hProcess Then ReDim lModules(1023) If EnumProcessModules(hProcess, lModules(0), 1024 * 4, lRet) Then sName = String$(MAX_PATH, vbNullChar) GetModuleBaseName hProcess, lModules(0), sName, MAX_PATH sName = Left$(sName, InStr(sName, vbNullChar) - 1) If Len(sName) = Len(sProcess) Then If sProcess = UCase$(sName) Then IsProcessRunning = True: Exit Function End If End If End If CloseHandle hProcess Next N End If End Function
Desde ya muchas gracias
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17
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Programación / Programación Visual Basic / Funcíon siendo detecta por los antivirus
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en: 8 Junio 2015, 03:17 am
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hola, tengo una función del un Stub en un joiner (Función "split") que está siendo detectado por antivirus en la siguiente línea: Esta línea es una de las más importantes de esta función Por favor, alguien me podría ayudar con alguna modificación para esta función? Segue lo código de la Funcíon: Private Function Separa(ByVal V1 As String, Optional ByVal V2 As String, Optional ByVal V3 As Long = -1) As String()
Dim V40 As Long, V50 As Long, V6 As Long, V7 As Long, V8 As Long, V9() As String
V6 = Len(V1)
If V2 = vbNullString Then V2 = " " V7 = Len(V2)
If V3 = 0 Then GoTo QuitHere If V6 = 0 Then GoTo QuitHere If InStr(1, V1, V2, vbBinaryCompare) = 0 Then GoTo QuitHere
ReDim V9(0) V40 = 1 V50 = 1
Do If V8 + 1 = V3 Then V9(V8) = Mid$(V1, V40) Exit Do End If
V50 = InStr(V50, V1, V2, vbBinaryCompare)
If V50 = 0 Then If Not V40 = V6 Then V9(V8) = Mid$(V1, V40) End If Exit Do End If
V9(V8) = Mid$(V1, V40, V50 - V40) V8 = V8 + 1
ReDim Preserve V9(V8)
V40 = V50 + V7 V50 = V40 Loop
ReDim Preserve V9(V8) Separa = V9
Exit Function
QuitHere: ReDim Separa(-1 To -1)
End Function
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